Confidence interval for the population proportion (\(p\))

Formula: \(\hat p \pm z^\* \sqrt{\frac{\hat p (1-\hat p)}{n}}\)
Sample proportion \(\hat p\) 50%
Sample size \(n\) 400
Confidence level (%) 95
Normal conditions
  • “Successes” \(n\hat p\) ≥ 10:
  • “Failures” \(n(1-\hat p)\) ≥ 10:
  • Both?
Normal conditions not met!
Parts of the result: \(z^\*\), \(se\), \(me\)
\(z^\*\)
\(\text{Standard Error } = \sqrt{\frac{\hat p (1-\hat p)}{n}} \;=\)
\(\text{Margin of Error } = z^\*(se) \;=\)
Confidence interval =
Range Shown (%) 0% – 100%